When the fume release rate is different from Vs, the optimum Vp flow line and the three sampling points have a X-direction velocity change of 1.0 m/s. The jet velocity should not exceed 0.8 m/s, and the jet velocity is 0.7 m. /s. The jet angle α is changed to determine the minimum exhaust speed Vp at each angle, see 3, wherein the angle is determined with the negative Y direction as the baseline and the clockwise direction as the positive direction. In the case of a jet air curtain, the split velocity in the Y direction at the sampling point plays a dominant role, affecting the flow pattern, and thus the split speed is used as a reference parameter.
It can be concluded that when the soot release rate is 1.0m/s and the jet velocity is 0.7m/s, the minimum exhaust velocity is 0°, 15°, 30° and 60° respectively. For 1.6m/s, 1.6m/s, 1.7m/s and 1.6m/s, the jet angle has little effect on the exhaust, so the angle is 0° without considering the influence of the kitchen operation. Compared with the above-mentioned deep type hood, the exhaust air speed required by the new exhaust hood is reduced, and at the same time, it can be seen from the streamline that the amount of air extracted from the working area of ​​the kitchen personnel is reduced, that is, the loss of indoor air is reduced. , saving energy.
Energy-saving analysis Through the above calculations, it can be found that in the absence of a jet air curtain, it can be found from the various streamlines that the substances discharged by the range hood include the fumes emitted from the pot and the air conditioner in the kitchen space. In two parts of the air, the air-conditioning air is discharged in large quantities, wasting energy. The two-part exhaust air volume is expressed by the following formula: Q=Q1+Q2(1) where Q? exhaust hood exhaust air volume, m3/s; Q1? soot emission, m3/s; Q2? discharged indoor air conditioning air volume , m3/s.
From the results of the above simulation calculation, it can be obtained that when the soot release speed Vs is 1.0 m/s, the minimum exhaust speed Vp required to set the jet air curtain is 1.9 m/s, as shown in 1a), the exhaust is exhausted. The diameter of the outlet surface is "280mm" or 0.28m, the diameter of the flue release outlet surface is "350mm" or 0.35m, and the air density is Ï, then: Q = Ï Ã— 1.9 × 0.282 × Ï€ / 4 = 0.1169Ï, Q1 = Ï Ã— 1.0 × 0.352 × Ï€ / 4 = 0.019616Ï, Q2 = Q - Q1 = 0.02074Ï.
The soot release velocity Vs is 1.0 m/s, and the minimum exhaust velocity Vp is 1.6 m/s when the jet air curtain is set, as shown by 1b), and the diameter of the exhaust outlet surface is "280 mm" or 0.28 m, and the soot release outlet The surface diameter is "350mm" or 0.35m, then: Q = Ï Ã— 1.6 × 0.282 × Ï€ / 4 = 0.089847Ï, Q1 = Ï Ã— 1.0 × 0.352 × Ï€ / 4 = 0.019616Ï, Q2 = Q - Q1 = 0.00231Ï .
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